Prove: the sum of even integers is even.
Proof: Given a pair of even integers m and n, which can be written as 2i and 2j, where i and j are integers. Consider the sum m + n: m + n = 2i + 2j, or 2(i+j). Since 2 is a factor of this integer, the sum m + n is also even. Q.E.D.
Prove: If a number x is positive, so is x+1.
Proof: In this case, P(x) is the statement ``x is positive'', and Q(x) is ``x+1 is positive''. To prove by contraposition, we attempt to prove that, if x+1 is not positive, then x is not positive. Hence, assume that x+1 is not positive (i.e., ). Then , which implies that x is not positive.
Prove: If x is an even prime number, then x=2.
Proof (by contradiction): Suppose that x is an even prime, but that . Then x=2k, where k is an integer greater than 1. But this contradicts the fact that x is prime!
Prove: The sum of the integers from 1 to 100 is 5050.
Since this is simply a sum, we need only add up the numbers. Gauss was a precocious student, and his teacher, to amuse him for a long time, gave him this exercise when he was but a young school boy. Unfortunately for the school master, Gauss was back at his desk a few minutes later with the answer.
Proof (by ``serendipity''): Gauss broke the integers into pairs, and added them together:
and there are 50 such pairs, so the sum is 5050.