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We concluded that, if the starting number was a Fibonacci number, then it was best to go second (be player 2); if not Fibonacci, try to be player 1.
We concluded that it comes down to this fact:
Every natural number is either
Two things:
Write the number of counters as a sum of non-consecutive Fibonacci numbers, and take the smallest in the sum.
The English puzzlist, Henry E Dudeney (1857 - 1930, pronounced Dude-knee) wrote several excellent books of puzzles (see after this section). In one of them he adapts Fibonacci's Rabbits to cows, making the problem more realistic in the way we observed above. He gets round the problems by noticing that really, it is only the females that are interesting - er - I mean the number of females!
He changes months into years and rabbits into bulls (male) and cows (females) in problem 175 in his book 536 puzzles and Curious Problems (1967, Souvenir press):
If a cow produces its first she-calf at age two years and after that produces another single she-calf every year, how many she-calves are there after 12 years, assuming none die?
This is a better simplification of the problem and quite realistic now.
Why does it happen? Some folks believe that it's because of the way things grow, suggesting something like this.
Let's revisit Pascal's triangle, and discover Fibonacci numbers therein: