Last time | Next time |
Today:
Questions about the homework?
However, don't forget order of precedence: if you said
"Violets are not blue or roses are red only if sugar is sweet."
then order of precedence would have us interpret that as
"(Violets are not blue or roses are red) only if (sugar is sweet)."
Whoops! Dang our language....
Having proven (in 47) that $\land$ and $'$ together generate all five connectives, you simply show that $\lor$ and $'$ generate $\land$ (e.g. via truth table).
Alternatively, you can replicate #47 (producing $\lor$ and $\longrightarrow$ using $\lor$ and $'$ -- twice as much work!).
One of you proved that $A\land B \iff (A \longrightarrow B')'$: how would you like to say that "(I only if not my brother) -- Not" instead of "my brother and I"....? :)
Here's our mocked up version.
Links:
On a set containing all sets: Russell's paradox.
"Russell's paradox is the most famous of the logical or set-theoretical paradoxes. The paradox arises within naive set theory by considering the set of all sets that are not members of themselves. Such a set appears to be a member of itself if and only if it is not a member of itself, hence the paradox.
"Some sets, such as the set of all teacups, are not members of themselves. Other sets, such as the set of all non-teacups, are members of themselves. Call the set of all sets that are not members of themselves S. If S is a member of itself, then by definition it must not be a member of itself. Similarly, if S is not a member of itself, then by definition it must be a member of itself. Discovered by Bertrand Russell in 1901, the paradox has prompted much work in logic, set theory and the philosophy and foundations of mathematics."