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I mention one old project today, that might serve as a model for you.
So there is redundancy in how one chooses to map the parallel edges, in particular.
(Upshot -- don't waste your time! It's precious....)
Do you see the cube? Another way of thinking/working is to give a name to a graph (showing that they're both isomorphic to a familiar graph). They're both (distorted) cubes.
Here's what Griffin saw (and I liked):
The exam will cover everything from
If you check out this code, you'll see where I compute the power set ("all-subsets") of a set, to cover all the bases. I think that the end result is pretty beautiful, too!
(coded up following our author's algorithm, in section 3.3, p. 214, as closely as possible).