Checkpoint 5 Answers

1. There are two parts of the simplification: First, `|x|^(2n+3)=|x|^2 |x|^(2n+1)`. Second, `(2n+3)! =(2n+3)(2n+2)(2n+1)cdots3cdot2cdot1=(2n+3)(2n+2)(2n+1)!`.
2. 0.0233
3. -0.93758
4. `sin 5=-0.95892`. The actual error is 0.0213. Thus the error bound is fairly close — within about 10% of the actual error.