Comment on Activity 1

We have supplied a reason for each of the remaining steps to the right of the corresponding result.

`(du)/(dt)` `=(pt^(p-1))/(qu^(q-1))`  
  `=p/q(t^(p-1))/(u^(q-1))` This is a rule for multiplication of quotients.
  `=p/q(t^(p-1))/((t^(p//q))^(q-1))` We substituted for `u.`
  `=p/q (t^(p-1))/(t^((q-1)p//q))` A power `x^n` itself raised to the power `m` is `x^(mn).`
  `=p/q(t^(p-1))/(t^(p-p//q))` We carried out the multiplication in the exponent.
  `=p/qt^(p-1-p+p//q)` We used properties of exponents
  `=p/qt^(-1+p//q)` We cancelled `p` and `-p.`
  `=rt^(r-1)` We substituted `r=ptext[/]q.`