Comment on Activity 1

1. At terminal velocity `(dv)/(dt)=0,` so for that velocity `v`_term,

   `g-kv`_term`=0.`

   From this you can conclude that the terminal velocity is approximately `0.612` ft/sec.

2. Using the terminal velocity calculated in (a), it would take approximately one hour and `22` minutes to fall `3,000` feet.