Checkpoint 2 Answers

1. This is the result of Checkpoint 1.

2. `Ftext[(]t text[)]=Gtext[(]t text[)]+C` for all `t` in `[a,b]` — in particular for `t=b`.

3. We know that `C=-Gtext[(]a text[)]`.

4. This is the result of substituting from the third line into the first.