Changing to polar coordinates isn't too bad: we just switch from
describing our region using Cartesian coordinates $x$ and $y$, and move
to polar coordinates $r$ and $\theta$, via the transformation equations
\[
r^2=x^2+y^2 \hspace{1in}
x=r\cos{\theta} \hspace{1in}
y=r\sin{\theta}
\]
For "Polar rectangle" $R=\left\{ (r,\theta)\
|\ a\le{r}\le{b},\ \alpha\le\theta\le\beta\right\}$, substitution gives
\[
\int\!\!\!\int_{R}f(x,y)dA =
\int_{\alpha}^{\beta}\int_{a}^{b}f(r\cos(\theta),r\sin(\theta))r dr d\theta
\]
Notice that the differential of area, $dA$, has been replaced by $r dr
d\theta$: take a look at Figures 3, 4, and 5, p. 1022/23:
I jokingly refer to this as pirate integration: that "r dr" is too much fun!