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So we were learning how to calculate sample size to achieve a certain sized confidence interval.
If so, the normal distribution of $\hat{p}$ has mean $p$, and standard deviation ${\sqrt{\frac{p(1-p)}{n}}}$.
The more confidence desired, the larger the CI required (so it's harder for the true value to "leak out").
The larger the sample size, the smaller the CI for given confidence.
Since we don't know $p$ (that's what we're after), we have a choice -- we can use a good estimate for $p$, or use the conservative value $p=0.5$ -- that leads to largest value of $n$.
But this large value of $n$ assures us that we achieve the $MOE$ required.