Fermat's Last Theorem
So we left things at all solutions of
which can be written as
for integers s>t>0 such that gcd(s,t)=1 with . In particular, there ARE integer solutions of that equation (1); so what about
One observation is that, if n=pq, then
and
so that we simultaneously have solutions for all powers which are factors of n. Thus it suffices to ask if we can solve
for primes p: if we can't solve it for the prime factors of n, then we can't solve it for n itself.
Since we CAN find solutions for p=2, it's certainly possible that we have solutions for , for . Fermat, however, took care of that....
Andrew Wiles recently (1994) proved that no solutions in integers exist for any power n greater than 2. In this section, we see how Fermat (who professed to have a proof of this theorem) solved the case of n=4.
Theorem 11.3: The Diophantine equation has no solution in the positive integers x, y, and z.
Proof: by Fermat's method of ``infinite descent'': one obtains from a triple a strictly smaller triple, and so on ad infinitum; but the positive integers cannot be reduced ad infinitum - contradiction!
Corollary: The equation has no solution in the positive integers x, y, and z.
Corollary: The equation has no solution in the positive integers x, y, and z.
Hence, the only exponents of interest left to prove are odd primes....
Theorem 11.4: The Diophantine equation has no solution in the positive integers x, y, and z.
``It is impossible to write a cube as a sum of two cubes, a fourth power as the sum of two fourth powers, and, in general, any power beyond the second as a sum of two similar powers. For this, I have discovered a truly wonderful proof, but the margin is too small to contain it.''
Fermat proved the case n=4, and hence n=4k.