#1: When evaluating using either method, every calculation
must incorporate the method. The most "forgotten" calculation
was the .
#2: This one went pretty well, although I'd hoped for a
little more explanation for your choices. The best response
actually included the complete solution: the real line can be
divided up into five different regions, and starting from each
of which the convergence is qualitatively different (the fifth,
not mentioned on the key, is x=0).
#3: You can see the roots (-2, -1, 0, 1, 2), and they're
all simple. That means that the sign changes between roots. In
one single iteration, you'll find only a single root bracketed
by two guesses.
#4: I was truly surprised that folks couldn't give bounds
on the approximation of f by a quadratic Taylor
polynomial. I even gave the bounding formula, and the function
one needs to bound! (Some skipped over the word "quadratic",
and considered higher order Taylor polynomials.)
#5: Part a: show that
in each case; Part b: check derivatives
of each.
#6a: No one who attempted part a got it.
You definitely should know that
for all x>0; you can use that, and a few variables changes and
inequalities later show the result.
You could turn to the Taylor polynomial and error,
to show that the convergence is of order .