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The binomial theorem is another algebra problem for folks, and provides another way to pull a rabbit out of my ... hat!
The derivative of the monomial $x^n$ is $nx^{n-1}$, and
The derivative of the monomial $c x^n$ is $nc x^{n-1}$ (by constant multiple).
A polynomial is just a sum of these. So we apply the sum rule, and the power rule, and the constant multiple rule to the flight of the eraser, to get
$s'(t)=(at^2+bt+c)'=2at+b$
and
$s''(t)=(2at+b)'=2a$
$\left(\frac{f(x)}{g(x)}\right)'=\frac{f'(x)g(x)-f(x)g'(x)}{g(x)^2}$
Arc Length: $L = \theta r$
Again, this is an example of a linear relationship: $L$ is proportional to each of $\theta$ and $r$. So
We will derive the derivative of the sine function from the limit definition of the derivative (although we can see the derivative graphically above).
There are exactly three important trig identities one needs to know (all the others can be derived from these three):
So let's see how to derive the derivative of the sine from the MIDIC -- the limit definition of the derivative -- using the second of these identities.
Then the derivative of the cosine can be derived by simply shifting the sine function, and using the second trig identity above.