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Today:
Some comments:
no sweat (because the "if" starts an implication, completed by "sweet"; however, if you write
then there's a risk of confusion: is it $V \lor (RR \longrightarrow S)$ or is it $RR \longrightarrow (V \lor S)$? The language is confusing....
That's when you rely on punctuation:
If you arrive at a contradiction, then the implication must never be false -- i.e. always true: a tautology.
So you're looking for a contradiction. Point the contradiction out explicitly when you find it.
More on this today, in section 2.1.
(Since equivalence $\leftrightarrow$ is given in terms of an $\land$ and $\rightarrow$, it's covered once we do the others.)
Some comments:
If you have any issues with the grading let me know. Great job getting me the pdfs in legible formats! I am mostly interested in you trying the problems. (The answers are available on the web -- I know! I've probably seen all the answers before, copied by students in classes before you. I don't like to see answers that look like they're just copied down (e.g. from the back of the book) -- makes me feel like I'm wasting my time grading them, and I'm pretty sure that students who do it aren't really learning anything. It's always wonderful to see some interesting attack on a problem by a student; I appreciate the struggle!)
Please save your work as a single pdf (lots easier for me to grade), and upload that to Canvas. Remember to keep the grader happy! You don't want a grumpy grader, trust me; they're not nearly as sympathetic!:)
On a set containing all sets: Russell's paradox.
"Russell's paradox is the most famous of the logical or set-theoretical paradoxes. The paradox arises within naive set theory by considering the set of all sets that are not members of themselves. Such a set appears to be a member of itself if and only if it is not a member of itself, hence the paradox.
"Some sets, such as the set of all teacups, are not members of themselves. Other sets, such as the set of all non-teacups, are members of themselves. Call the set of all sets that are not members of themselves S. If S is a member of itself, then by definition it must not be a member of itself. Similarly, if S is not a member of itself, then by definition it must be a member of itself. Discovered by Bertrand Russell in 1901, the paradox has prompted much work in logic, set theory and the philosophy and foundations of mathematics."