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'Mind blowing': quantum computer untangles the mathematics of knots: Algorithms for studying knots and other topological objects could have a quantum advantage.
Knot invariants are typically calculated from patterns of crossings - how the threads in a knot cross over each other when the knot is flattened on a surface - but depend only on the knot's topological type. In other words, the same knot can be flattened in two different ways, with vastly different crossing patterns, but the knot invariant will still be the same. If two crossing patterns have different knot invariants, it means that they come from knots that are topologically distinct.
"Why is topology so inherent to quantum computation? I think this is a very deep question," says Aharonov. The answer, she adds, could be linked to the fact that in quantum physics, many particles can share a collective 'entangled' state, and there are quantum states that maintain their quantum information even if they change at a local level. Having properties that don't change when an object undergoes a local deformation is "very much the essence of topology", she says.
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This is the most beautiful piece of mathematics I know:
It turns out that there are golden rectangles in the heart of an icosahedron, interlocked as Borromean rings!
We made some using 3x5 (or 4x6) cards -- which are not quite golden. Their corners are the 12 vertices of the icosahedron. The tricky part is locking them together!
But we can easily figure out which is which, because the knot is a single continuous piece of material, whereas the link is two separate pieces of material.
It's all about overs and unders!
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Type I | Type II | Type III |
The third images on that page stems from this picture from a recent Science issue:
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In order to consider the picture on the left a knot, we have to know what its ends are doing. In the figure at right, I assumed that they are just connecting to each other in the simplest way.
The succession of steps then go on to show that the knot is actually an unknot! That's good news for the hyperbusy people!
Here's another picture of an unknot, which could trick you -- but knowing the R1 move saves you:
We'll just try a few with a string, to see what we can learn.
Reidemeister Move I is tricolorable. | Reidemeister Move II is tricolorable. | Reidemeister Move III is tricolorable. |
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So, for example: if you've got your picture of a knot down to three crossings, and it's not tricolorable, then it's the unknot.
Because the above written pair in the first month bore, you will double it; there will be two pairs in one month. One of these, namely the first, bears in the second montth, and thus there are in the second month 3 pairs; of these in one month two are pregnant and in the third month 2 pairs of rabbits are born, and thus there are 5 pairs in the month; ...
there will be 144 pairs in this [the tenth] month; to these are added again the 89 pairs that are born in the eleventh month; there will be 233 pairs in this month.
To these are still added the 144 pairs that are born in the last month; there will be 377 pairs, and this many pairs are produced from the abovewritten pair in the mentioned place at the end of the one year.
You can indeed see in the margin how we operated, namely that we added the first number to the second, namely the 1 to the 2, and the second to the third, and the third to the fourth and the fourth to the fifth, and thus one after another until we added the tenth to the eleventh, namely the 144 to the 233, and we had the abovewritten sum of rabbits, namely 377, and thus you can in order find it for an unending number of months.