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Here's a menu of our past zooms...
I'll post the link to today's later. These zooms will continue through February 7th, for those who can't attend in person.
I asked you to bring the Preview Activity and the Completed worksheet to class, to submit for my perusal. I just want to get a look at your work.
Also carry out the following two exercises (due next Monday, at 2:00 pm (before class), to submit on Canvas): Section 1.1, #8; Section 1.2, #7.
"In the two-minute span, there were three lead changes and a tie. Twenty-five points scored. The quarterbacks combined for 221 passing yards and three touchdowns in the same period."
And how is all of this illustrated in the "win probability chart"?
The key to that "instantaneous" velocity is something called an "indeterminate form", and limits. We'll get a look at that in the activity we do next, but it's hinted at by thinking about average velocity: as we noted last time, it's a change in $y$ over a change in $x$:
\[ AV = \frac{\textrm{change in y}}{\textrm{change in x}} \]
Now what happens as that "change in $x$" approaches 0? (that's the "limit" part!)
If all is well in the world, then the ratio becomes indeterminate because the "change in $y$" also approaches 0! And everyone knows what $\frac{0}{0}$ is, right? (that's the "indeterminate" part!)
\[ \begin{equation*} IV_{t=a} = \lim_{b \to a} AV_{[a,b]} = \lim_{b \to a} \frac{s(b)-s(a)}{b-a}\text{.} \end{equation*} \]
or, equivalently,
\[ \begin{equation*} IV_{t=a} = \lim_{h \to 0} AV_{[a,a+h]} = \lim_{h \to 0} \frac{s(a+h)-s(a)}{h}\text{.} \end{equation*} \]
We interpret the derivative as the slope of the tangent line (the limit of secant lines!) at a point. You can frequently look at a graph and see where things go awry. Take a look at the football graph above, and describe where problems exist. For example, if there's no tangent line at a point, then there's no instantaneous velocity!