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Also carry out the following two exercises: Section 1.1, #8; Section 1.2, #7.
These will test your comprehension of important elements of these sections.
Last time we were looking at Section 1.1: How do we measure velocity?
The key to that "instantaneous" velocity is something called an "indeterminate form", and limits. We'll get a look at that in the activity we do next, but it's hinted at by thinking about average velocity: as we noted last time, it's a change in $y$ over a change in $x$:
\[ AV = \frac{\textrm{change in y}}{\textrm{change in x}} \]
Now what happens as that "change in $x$" approaches 0? (that's the "limit" part!)
If all is well in the world, then the ratio becomes indeterminate because the "change in $y$" also approaches 0: $\frac{0}{0}$ is what makes this "indeterminate".
One thing we haven't done yet is see how Desmos can help us investigate secant lines
And because we want to talk about what's going on from the left of \(a\) and what's going on to the right of \(a\), we considered the so-called "one-sided limits": from the left:
\[ \begin{equation*} \lim_{x \to a^-} f(x) = L \end{equation*} \]
and from the right:
\[ \begin{equation*} \lim_{x \to a^+} f(x) = L \end{equation*} \]
So in this graph,
we can say that \[ \begin{equation*} \lim_{x \to 1^-} g(x) = 3 \end{equation*} \]
and from the right:
\[ \begin{equation*} \lim_{x \to 1^+} g(x) = 2 \end{equation*} \]
\[ \begin{equation*} IV_{t=a} = \lim_{b \to a} AV_{[a,b]} = \lim_{b \to a} \frac{s(b)-s(a)}{b-a}\text{.} \end{equation*} \]
or, equivalently,
\[ \begin{equation*} IV_{t=a} = \lim_{h \to 0} AV_{[a,a+h]} = \lim_{h \to 0} \frac{s(a+h)-s(a)}{h}\text{.} \end{equation*} \]
Then we'll have a look at Exercise 1.2.4
We interpret the derivative as the slope of the tangent line (the limit of secant lines!) at a point. You can frequently look at a graph and see where things go awry. For example, if there's no tangent line at a point, then there's no instantaneous velocity!