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By the way, the quiz will be over section 1.5.
I pushed back your 1.5 assignment, now due Thursday.
The most important definition in calculus is the derivative function (here is the derivative of $f$ at $x$):
And that's why we're so concerned about limits! Memorize it. Be able to write it at a moment's notice.
We can approach $x=a$ from the left or from the right. We define limits from the left and from the right, and then say that the limit exists as $x$ approaches $a$ if and only if the limits from the left and right exist, and agree: if \[ \lim\limits_{x \to a^-}f(x) = L \] and \[ \lim\limits_{x \to a^+}f(x) = L \] then \[ \lim\limits_{x \to a}f(x) = L \]
We had a look at a few problems from the text (pp. 59--), and discovered that, if we have the graph of a function, then the limits are pretty easy to see.
Let's check out some Mathematica examples from section 1.5, and check out not only the limits, but also what dangers lurk, even when we have very good technology (see Example 2, Figure 5, p. 52). You can't always trust your calculator; trust your brain first.
We'll be using Mathematica extensively in this class. Have I told you that you have the right to a free copy of Mathematica?
So limits may be infinite (one-sided, perhaps). Here's how we define that:
infinite limits for $\displaystyle f(x)$ as $\displaystyle x$ approaches $\displaystyle a$: \[ \lim\limits_{x \to a}f(x) = \infty \] means that the values of $\displaystyle f(x)$ can be made arbitrarily large (as large as we please) by taking $\displaystyle x$ sufficiently close to $\displaystyle a$ (but not equal to $\displaystyle a$). Similarly we can define \[ \lim\limits_{x \to a}f(x) = -\infty \] and one-sided limits such as \[ \lim_{x \to a^-}f(x) = \infty {\hspace{1.5in}} \lim\limits_{x \to a^+}f(x) = \infty \]
In any of these cases, we define a vertical asymptote of the curve $\displaystyle y=f(x)$ at $\displaystyle x=a$.
Note the symmetry, which allows us to check only one side.
Symmetry is a very important (and under-discussed) aspect of mathematics. Keep an eye on even and odd functions.
Here the function $f(x)=1$ is plotted. As $x \to 0$, the $y$-values head to
1. Well, more to the point, they never vary from 1!
Quite a boring function.... |
Here the function $f(x)=x$ is plotted. As $x \to 0$, the $y$-values head to
0. And the closer $x$ gets to 0, the closer $y$ gets to 0. That's the way it's
supposed to work!
Also a rather boring function: so predictable! |
What can we do with those? We need more horsepower....
So what is this limit:
This sum (and many other operations) satisfy the same pattern:
So, in particular,
Suppose that $\lim_{x \to a} f(x)$ and $\lim_{x \to a} g(x)$ exist. Then \[ \lim_{x \to a} [f(x)+g(x)] = \lim_{x \to a} f(x) + \lim_{x \to a} g(x) \] \[ \lim_{x \to a} [f(x)-g(x)] = \lim_{x \to a} f(x) - \lim_{x \to a} g(x) \] \[ \lim_{x \to a} [cf(x)] = c\lim_{x \to a} f(x) \] \[ \lim_{x \to a} [f(x)g(x)] = \lim_{x \to a} f(x) \lim_{x \to a} g(x) \] \[ \lim_{x \to a} \frac{f(x)}{g(x)} = \frac{\lim\limits_{x \to a} f(x)}{\lim\limits_{x \to a} g(x)} {\text{ if }} \lim_{x \to a} g(x) \ne 0 \]
\[ \lim\limits_{x\to{0}}\sqrt{x} \]
Because the function isn't even defined as x approaches 0 from the left (square roots of negative numbers are imaginary). So we have only a one-sided limit, that \[ \lim\limits_{x\to{0^+}}\sqrt{x}=0 \] Of course we can say that \[ \lim\limits_{x\to{1}}\sqrt{x}=1 \] Limits exists everywhere else on the domain of the sqrt function. |
This is the conclusion of Exercise #55, p. 71, which says that polynomials are continuous, which we'll consider more in section 1.8.
Exercise #56 says it's also true for rational functions, for every element of their domain.
In this case, both show examples of a slightly different version of this most important definition, the derivative at a point $x=a$:
What's happening to the $y$-values?