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Here's today's zoom, and the Play-by-Play
Here's the day02 play-by-play. I had to redo what we did in class, because I forgot to record it, but it might be good to see it again.
In particular we modelled "Linear stuff": if I double $x$, do I double $y$? If so, the relationship is linear.
We concluded that new infections are linearly related to both the size of the infected population, and the size of the susceptible population.
Vaccines, on the other hand, essentially set up a pathway directly from susceptible people to recovered people -- removing them as prospective targets of Covid, and cutting into new infections.
What we know from SIR models is that Public health requires public-level solutions.
(and let's forget about boosters -- just the first round)
So your privacy is respected, but we also get a good idea of how well vaccinated you are as a group.
:) Is is comforting to know that we're relying on that stuff? Maybe trees sound best, but these aren't the trees you're probably thinking of. Instead, they're a kind of graph (surprise!).
Here's your Tree Terminology page. You should learn those definitions. I'll be using some of them today, and will give you some definitions as we go.
When you do your reading for next time (Chapter 23: Chances Are), you might try to imagine how I'm going to use trees to help illustrate what the author describes (Strogatz could have used some trees to make things clearer!).
One experiment we'll pass on, because it doesn't allow enough lying; the second one will allow everyone to lie!:) We'll go with that...
NB: important! I messed up the final calculation! I was in a hurry to "beat the clock", and made an error which resulted in an estimate of 40% for the vaccination rate of NKU students. (Can you find my error?)
In actuality, the estimate should have been 70%. Big difference! Here is the proper calculation:
The measured rate of vaccination was $r_v$, which got a contribution of $\frac{3}{4}r$ from the vaccinated, and $\frac{1}{4}(1-r)$ from the unvaccinated: \[ r_v=\frac{3}{4}r + \frac{1}{4}(1-r) \] Now we solve that for $r$: \[ r_v=\frac{1}{2}r + \frac{1}{4} \] or \[ r_v - \frac{1}{4} =\frac{1}{2}r \] Solving for $r$, we get our final formula: