Last time | Next time |
If there are any particular issues we need to address, to make things better, please let me know.
I'll hope to have the exams graded in the next couple of days.
(here it is as a .nb)
(The ones featured in today's materials are actually from Calc I chapters of Stewart.)
p[x_]:=Log[3/(1 + x^2)] xleft = -Sqrt[2] xright = Sqrt[2] z[x_]:=1 RevolutionPlot3D[{{p[x] + 1}, {z[x]}}, {x, xleft, xright}, RevolutionAxis -> {1, 0, 0}]Punch that in, and you'll see a beautiful volume of rotation about the line $y=-1$:
Looks like Matt actually shifted the function up one unit, then reflected it about the $x$-axis, and then removed a cylinder of radius 1 about the $x$-axis. This produces the identical figure, and its computed volume will be the same as the original object.