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The power rule works for any real exponent (except 0 -- what's wrong with 0?) -- it's just that we've only proven it for positive integers. You may use it for other powers (so write $\sqrt{x}=x^\frac{1}{2}$, for example, to make use of this nice new rule!).
By the way, once we've proven the chain rule, we'll be able to prove the power rule for any real exponent, using exponential functions and their inverses (logs).
If we need the derivative of \[ f(x)=4x^3-7x^2+5x-1 \]
it's easy now!
This says that an exponential function has a slope function which is just a constant times the function itself (and the constant is the log, base \(e\), of \(a\)).
In particular, let $F(x)=e^x$, where $e \approx 2.71828$ (it's irrational, like $\pi$). Then \[ \frac{d}{dx}[F(x)] = F(x) \hspace{1in} (= F'(x) = F''(x) = F'''(x) = ....) \]
This is certainly one of the most amazing rules. It says that $e^x$ is an exponential function which is its own derivative: whose values are its slopes, as well (and all its higher derivatives as well -- its concavity, its jerk, ...).
Here's an animation which motivates the discussion...
But this can be proved as a corollary of the product rule, by this one simple little trick....
(By the way, the polynomials are merely a subset of the rational functions: they're the rational functions with constant polynomials for denominators.) \[ f(x)=4x^3-7x^2+5x-1=\frac{4x^3-7x^2+5x-1}{1} \]
See? So what's the derivative of \[ F(x)=\frac{x^2-3x-4}{x-2} \]
Derivatives of rational functions are easy now! (No more limit definition derivations for you -- at least most of the time). But we still have a few more rules to prove....